In the given figure, AB || CD. If ∠EAB = 50° and ∠ECD = 60°, then ∠AEB = _______ degrees.

70

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Solution

The correct option is A 70
AB ∥ CD and BC is transversal.
∴ ∠ABE = ∠ECD = 60°
[Alternate interior angles]

In ∆ABE, we have:
∠EAB + ∠ABE + ∠AEB = 180°
[Angle sum property of a triangle]

⇒ 50° + 60° + ∠AEB = 180°
⇒ ∠AEB = 70°

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Similar questions

In the given figure, AB||CD. If $∠ E A B = 50^{\circ}$ and $∠ E C D = 60^{\circ}$ then $∠ A E B = ?$

$(a) 50^{\circ}$

$(b) 60^{\circ}$

$(c) 70^{\circ}$

$(d) 55^{\circ}$

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