Question

In the given figure, AB || CD, then $\angle$ EFD is equal to:

• A. 20${}^o$
• B. 25${}^o$
• C. 30${}^o$
• D. 35${}^o$

Answer 1

The correct option is C 30${}^o$

$\angle EFD=?$

$\angle ABC=\angle DCE={60}^o$ (corresponding angles )

$\therefore \angle FCE=180-60={120}^o$ (Property of traversal line)

But, $\angle FCE+\angle CEF+\angle CFE={180}^o$ (Property of triangle)

$\therefore \angle CFE=180-120-30=180-150={30}^o$.