In the given figure AB = DC and AD = 5 cm. Find BC.

5 cm

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4 cm

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3 cm

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6 cm

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Solution

The correct option is A 5 cm
In $△ A B C$ and $△ A D C$ ,

AB = DC (given)

AC = AC (common side-hypotenuse)

$∠ B$ = $∠ D = 90^{\circ}$

$∴ △ A B C ≅ △ A D C$ by RHS criterion.
Therefore, BC = AD = 5 cm ..... (corresponding parts of congruent triangle)

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In the given figure AB = DC and AD = 5 cm. Find BC.

The correct option is A 5 cmIn △ABC and △ADC, AB = DC (given) AC = AC (common side-hypotenuse) ∠B=∠D=90∘ ∴△ABC≅△ADC by RHS criterion. Therefore, BC = AD = 5 cm ..... (corresponding parts of congruent triangle)

The correct option is A 5 cm
In $△ A B C$ and $△ A D C$ ,

AB = DC (given)

AC = AC (common side-hypotenuse)

$∠ B$ = $∠ D = 90^{\circ}$

$∴ △ A B C ≅ △ A D C$ by RHS criterion.
Therefore, BC = AD = 5 cm ..... (corresponding parts of congruent triangle)