In the given figure- AB-DC and BD-CA- Prove that - ABC- DCB-

Given AB=CD BD=CA In ABC amp; DCB BC=BC (Common side) ∴ By SSS congurency ABC≅ DCB #160; #160; ...

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SSS Criteria for Congruency

In the given ...

Question

In the given figure, $A B = D C$ and $B D = C A$ . Prove that $Δ A B C ≅ D C B$ .

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Solution

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∠ D A B = ∠ D C B .

A r e a (Δ D C B) = A r e a (Δ A C B)

A B ∥ D E

B D ∥ E F

D C^{2} = C F \times A C

∠ A B C = 90^{o}

B D ⊥ A C

[Δ A B C \sim Δ B D C \Rightarrow \frac{A B}{B D} = \frac{B C}{D C}]

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