In the given figure, AB is a tangent to the circle with centre P. Using the information given in the figure, find $∠ B A M$ .

$10^{\circ}$

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$20^{\circ}$

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$30^{\circ}$

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$40^{\circ}$

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Solution

The correct option is B
$20^{\circ}$

$∠ C M B = 80^{\circ} + 30^{\circ} = 110^{\circ}$ .... (exterior angle theorem)

$∠ M B A = 90^{\circ}$ ...... (tangent perpendicular to the tangent at the point of contact)

$∠ B A M = 110^{\circ} - 90^{\circ} = 20^{\circ}$ .... (exterior angle theorem)

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