In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 6 cm and BC = 8 cm. Then, the value of AM is

3 cm

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4 cm

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5 cm

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7 cm

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Solution

The correct option is B
4 cm

$A C = \sqrt{{A B}^{2} + {B C}^{2}}$

$A C = \sqrt{6^{2} + 8^{2}}$ = $\sqrt{100} = 10 c m .$

Since median divides the side in two parts $A M = \frac{A C}{2} = 5 c m$

So, AM = 5 cm.

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Q. In the given figure,

△ A B C = 90^{o}

and

B M

is a median,

A B = 8 c m

and

B C = 6 c m

. Then, length

B M

is equal to:

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 6 cm and BC = 8 cm. Then, which of the following are true?

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In the given figure, ∠ABC = 90∘ and BM is a median, AB = 6 cm and BC = 8 cm. Then, the value of AM is

The correct option is B 4 cm AC=√AB2+BC2 AC=√62+82 = √100=10cm. Since median divides the side in two parts AM=AC2=5cm So, AM = 5 cm.

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 6 cm and BC = 8 cm. Then, the value of AM is

The correct option is B
4 cm

$A C = \sqrt{{A B}^{2} + {B C}^{2}}$

$A C = \sqrt{6^{2} + 8^{2}}$ = $\sqrt{100} = 10 c m .$

Since median divides the side in two parts $A M = \frac{A C}{2} = 5 c m$

So, AM = 5 cm.