In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 8 cm and BC = 15 cm. Then, the value of CM is

MC = 8.5 cm.

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MC = 6.5 cm.

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MC = 8 cm.

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MC = 7.5 cm.

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Solution

The correct option is A
MC = 8.5 cm.

$A C = \sqrt{{A B}^{2} + {B C}^{2}}$

$A C = \sqrt{8^{2} + 15^{2}}$

$A C = \sqrt{64 + 225}$

$A C = \sqrt{64 + 225} = \sqrt{289} = 17 c m .$

Since median divides the side in two parts AM = MC

So, AM = MC = $\frac{17}{2} = 8.5 c m$

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Similar questions

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 8 cm and BC = 6 cm. Then, choose the correct option(s).

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median drawn from B to AC, AB = 8cm and BC = 6 cm. Then, choose the correct option(s).

A B ∥ C R

L M ∥ Q R

B M / M C = A L / L Q

L M : Q R

B M : M C = 1 : 2

△ A B C, ∠ A B C = 90^{o}

AB = 4 BC

A M = 8 x^{2}, M C = 2 x^{2}

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