In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 8cm and BC = 6 cm. Then, length BM is equal to -

3 cm

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4 cm

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5 cm

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7 cm

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Solution

The correct option is C
5 cm

AC = $\sqrt{8^{2} + 6^{2}}$ = $\sqrt{100}$ = 10 cm.

So, AM = MC = 5cm.

Since the mid point of the hypotenuse of a right triangle is equidistant from its vertices, so

BM = AM = MC = 5cm.

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In the given figure, ∠ABC = 90∘ and BM is a median, AB = 8cm and BC = 6 cm. Then, length BM is equal to -

The correct option is C 5 cm AC = √82+62 = √100 = 10 cm. So, AM = MC = 5cm. Since the mid point of the hypotenuse of a right triangle is equidistant from its vertices, so BM = AM = MC = 5cm.

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 8cm and BC = 6 cm. Then, length BM is equal to -

The correct option is C
5 cm

AC = $\sqrt{8^{2} + 6^{2}}$ = $\sqrt{100}$ = 10 cm.

So, AM = MC = 5cm.

Since the mid point of the hypotenuse of a right triangle is equidistant from its vertices, so

BM = AM = MC = 5cm.