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Question

In the given figure, ABC is a right-angled triangle at B and EF is perpendicular on BC. If AF = 3 cm, AB =21cm and FC = 4 cm, then EF is equal to


A
43 cm
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B
734 cm
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C
47 cm
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D
437 cm
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Solution

The correct option is D 437 cm
As we know, if any two right triangles have an acute angle measure in common, the ratios of their corresponding side lengths will be equal.

In ΔABC and ΔFEC:


ABC=FEC .... Each 90

ACB=FCE (Common)

Thus, we see: ACFC=ABFE

Putting values we get:

4+34=21FE (AC=AF+FC)

74=21FE

FE=4×7×37

FE=437 cm

Hence, the correct answer is option (d).

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