In the given figure, ABCD is a parallelogram. If area ΔADP=30cm2 and area ΔBCP=24cm2, then area of ||gm ABCD =
(i)Through P draw PQ||AD||BC
(ii)APQD and PBCQ are parallelograms (opposits sides are parallel)
(iii)∴ area of ||gm APQD=2×area ΔAPD
=2(30) =60cm2
(iv) area of ||gm PBCQ = 2×area ΔPBC
=2(24) =48cm2
∴ area ||gm ABCD = 60+48
=108 cm2