Question

In the given figure, ABCD is a parallelogram of base 4 cm and height 4cm , then ar($\Delta AFB$) is

Answer 1

Area of parallelogram ABCD = $b\times h$
$=4\times 4$
$=16{cm}^2$
In $\Delta$ ABF and \\gm ABCD, both are having AB as base and lying between the same parallel lines (AB and CD).

($\because$ Area of a triangle is half the area of parallelogram if both are on the same base and between the same parallels).

$\therefore$ Area of $\Delta AFB=\frac{1}{2}\times$ Area of parallelogram ABCD

$=\frac{1}{2}\times 16=8{\text{cm}}^2$