Question

In the given figure, ABCD is a quadrilateral such that $DA\perp AB$ and $CB\perp AB$, x = y and EF || AD such that EF bisects $\angle DEC$. Then $C{D}^2$ is equal to

• A. None of these
• B. $2C{E}^2$
• C. $2D{E}^2$
• D. Both (a) and (b)

Answer 1

The correct option is D

Both (a) and (b)

Given,
ABCD is a quadrilateral with $DA\perp AB$ and $CB\perp AB$
and EF || AD
$\Rightarrow EF||BC$
$\Rightarrow EF\perp AB$
Now, in $\Delta DAE$ and $\Delta CBE$,
$\angle DAE=\angle CBE$ [each ${90}^{\circ }$]
Also, $\angle DEA=\angle CEB$
$\therefore \Delta DAE\sim \Delta CBE$ [by AA similarity]
$\Rightarrow \frac{DE}{AE}=\frac{CE}{BE}\Rightarrow DE=CE$ ...(i)
Now, in $\Delta DEC$, right angled at E,
$D{E}^2+C{E}^2=D{C}^2\Rightarrow 2D{E}^2=2C{E}^2=D{C}^2$