In the given figure, ABCD is a rhombus. Diagonals AC and BD intersect each other at E. ∠1=50o then ∠BCD=
A
100o
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B
90o
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C
80o
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D
none of these
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Solution
The correct option is C80o ABCD is a rhombus. Diagonals AC and BD intersect each other at E. Given, ∠1=50o BD bisects ∠ABC ( by property of rhombus) So, ∠ABC=2×50o=100o ∠ABC+∠BCD=180o ----(Interior angles on the same side of transversal) ∠BCD=180o−∠ABC=180o−100o=80o