Question

In the given figure ABCDE is a pentagon in which $DE=DC,AB=BC=CE=EA=25m$ and its total height is $41m$. Find the area of the pentagon.

Answer 1

Area of pentagon is=Area of square ABCE+Area of triangle EDC

Area of triangle is $\frac{1}{2}$ base $\times$ height.

Height$=41-25=16$

Base$=25$
$\therefore \frac{1}{2}\times 25\times 16=200m^2$
Area of square$=a^2$
$={25}^2=625m^2$
Area of pentagon is $625m^2+200m^2$
$=825m^2$