In the given figure, $∠ A B C = 90^{\circ}$ and $B M$ is a median drawn from $B$ to $A C, A B = 8 c m$ and $B C = 6 c m .$ Then, choose the correct option(s).

3 cm

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4 cm

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5 cm

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7 cm

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Solution

The correct options are
A
3 cm

B
4 cm

C
5 cm

In $△ A B C,$ applying Pythagoras Theorem:

$A C^{2} = A B^{2} + B C^{2}$

$\Rightarrow A C^{2} = 8^{2} + 6^{2}$

$\Rightarrow A C = \sqrt{8^{2} + 6^{2}} = \sqrt{100} = 10 c m .$

So, $A M = M C = 5 c m .$

Since, the mid point of the hypotenuse of a right angled triangle is equidistant from its vertices, so

$B M = A M = M C = 5 c m .$

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Similar questions

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 8 cm and BC = 6 cm. Then, length BM is equal to___________.

In the given figure, $∠ A B C = 90^{\circ}$ and $M$ is the mid-point of $A C$ , $A B = 8 cm$ and $B C = 6 cm$ . Then, choose the correct option(s).

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median drawn from B to AC, AB = 8cm and BC = 6 cm. Then, choose the correct option(s).

In the given figure, ∠ABC = $90^{\circ}$ and BM is a median, AB = 8 cm and BC = 6 cm. Then, choose the correct option(s).

△ A B C = 90^{o}

B M

A B = 8 c m

B C = 6 c m

B M

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