In the given figure, ∠DAB = ∠ABC = 90∘. Also if α + φ = 90∘ and α = 2φ. The the ratio of H and h is
α + φ = 90∘ -------- (I)
α = 2φ ------- (II)
Solving I and II, we get α = 60∘ and φ = 30∘
Let the length of base AB be x
In ΔABC,
tan60∘ = Hx=√3 [∵ tan60∘=√3]
and ΔABD,
tan30∘ = hx [∵ tan30∘=1√3]
⇒ Hh = 3