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Question



In the given figure, PQR = 90° , PQS = 90° , PRQ = α andQPS = θ Write the following trigonometric ratios.
(i) sinα, cosα , tanα
(ii) sinθ, cosθ, tanθ

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Solution



(i)
sinα = Opposite side of PRQHypotenuse=PQPR

cosα = Adjacent side of PRQHypotenuse=RQPR

tanα = Opposite side of PRQAdjacent side of PRQ=PQRQ

(ii)
sinθ = Opposite side of QPSHypotenuse=QSPS

cosθ = Adjacent side of QPSHypotenuse=PQPS

tanθ = Opposite side of QPSAdjacent side of QPS=QSPQ

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