In the given figure, AOB is a straight line and the rays OC and OD stands on it.
If ∠AOC = 65°, ∠BOD = 70° and ∠COD = x° find the value of x.

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Solution

Since AOB is a straight line, we have:

$∠ A O C + ∠ B O D + ∠ C O D = 180 ° or 65 ° + 70 ° + x ° = 180 ° (given) or 135 ° + x ° = 180 ° or x ° = 45 ° Thus, the value of x is 45$

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In the given figure, AOB is a straight line and the rays OC and OD stands on it. If ∠AOC = 65°, ∠BOD = 70° and ∠COD = x° find the value of x.

Since AOB is a straight line, we have: ∠AOC+ ∠BOD + ∠COD = 180°or 65°+ 70° + x° = 180° (given)or 135° + x° = 180°or x° = 45°Thus, the value of x is 45

In the given figure, AOB is a straight line and the rays OC and OD stands on it.
If ∠AOC = 65°, ∠BOD = 70° and ∠COD = x° find the value of x.

Since AOB is a straight line, we have:

$∠ A O C + ∠ B O D + ∠ C O D = 180 ° or 65 ° + 70 ° + x ° = 180 ° (given) or 135 ° + x ° = 180 ° or x ° = 45 ° Thus, the value of x is 45$