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Question

In the given figure, BA AC, DE DF, such that, BA = DE, BF = EC. Then, by which congruence rule is ABC DEF?


A

ASA

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B

SAS

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C
SSS
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D
RHS
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Solution

The correct option is D RHS

Given, BA AC, DE DF
and, BA = DE, BF = EC


From the figure, we see that
BC = BF + FC and FE = FC + EC.
Since FC is common in both BC and FE, and BF = EC (given), we must have, BC = FE.
Now, in ABC and DEF,
BC = FE (proved)
AB = DE (given)
BAC = EDF = 90 (given)
Therefore, ABCDEF
(by RHS congruence condition)


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