Question

In the given figure BD = DC and $\angle CBD={30}^{\circ }$, Find $\angle BAC$

• A. ${60}^{\circ }$
• B. ${20}^{\circ }$
• C. ${90}^{\circ }$
• D. ${10}^{\circ }$

Answer 1

The correct option is A

${60}^{\circ }$

BD=DC
$\angle BCD=\angle CBD={30}^{\circ }$
So, $\angle BDC={120}^{\circ }$
As ABCD is cyclic
$\therefore \angle BAC={60}^{\circ }$