In the given figure below, AD is a diameter. O is the centre of the circle. AD is parallel to BC and ∠CBD=32∘. Find ∠AOB (in ∘)
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Solution
Given: AD∥BC ∴∠ADB=∠DBC=32∘ (alternate angles) ∵OB=OD (radii of the circle) ∠AOB=2∠ODB (angle at the centre is twice the angle at remaining circumference) =2×32=64∘