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Basic Proportionality Theorem

In the given ...

Question

In the given figure, $D E ∥ B C$ , $A D = 2 c m$ , $D B = 3 c m$ and $A E = 1.6 c m$ . Then EC is equal to

A

1.2 cm

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B

2.5 cm

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C

2.4 cm

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D

4.8 cm

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Solution

The correct option is C 2.4 cm
Given,
$D E ∥ B C$
AD=2cm, DB=3cm, AE=1.6cm
as per problem,
$\frac{A D}{D B} = \frac{A E}{E C}$
$\frac{2}{3} = \frac{1.6}{E C}$
$2 E C = 4.8 c m$
$E C = 2.4 c m$

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