In the given figure, $∠ 1 = 70^{o}$ . Find $180^{o} - 2 ∠ x$ .

50^{o}

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40^{o}

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45^{o}

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60^{o}

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Solution

The correct option is B $40^{o}$
$∠ x = ∠ 1$ .....................[ Alternate angles]
$∴ ∠ x = 70^{o}$
$∴ 180^{o} - 2 ∠ x = 40^{0}$

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Similar questions

a) {90^{o}, 30^{o}, 50^{o}}

b) {40^{o}, 40^{o}, 100^{o}}

c) {50^{o}, 60^{o}, 70^{o}}

d) {20^{o}, 30^{o}, 40^{o}}

△ A B C

△ D E F

∠ A = 50^{o}, ∠ B = 70^{o}, ∠ C = 60^{o}, ∠ D = 60^{o}, ∠ E = 70^{o}, ∠ F = 50^{o}

△ A B C

\frac{{cos}^{2} 20^{o} + {cos}^{2} 70^{o}}{{sec}^{2} 50^{o} - {cot}^{2} 40^{o}} + 2 {cosec}^{2} 58^{o} - 2 cot 58^{o} tan 32^{o} - 4 tan 13^{o} tan 37^{o} tan 45^{o} tan 53^{o} tan 77^{o}

∠ A C B = 40^{o}

∠ A D B =

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