Question

In the given figure,$BC=CE$ and $\angle 1=\angle 2$ Then,
:$\Delta GCB\equiv \Delta DCE$
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

$\angle CBG={180}^{\circ }-\angle 1$
$\angle CED={180}^{\circ }-\angle 2$
Since, $\angle 1=\angle 2$
Thus, $\angle CBG=\angle CED$
Now, In $△GCB$ and $△DCE$,
$\angle CBG=\angle CED$ (Proved above)
$BC=CE$ (Given)
$\angle GCB=\angle DCE$ (Vertically opposite angles)
Thus, $△GCB\cong △DCE$...... (ASA rule)