Question

In the given figure drawn, seg $BE\perp$ seg $AB$ and seg $BA\perp$ seg $AD$. If $BE=8$ and $AD=12$, find $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}$.

Answer 1

Given, $\Delta ABE$ and $\Delta BAD$ have the same base.

Also given, $BE=8,AD=12$
$\therefore$ $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}=\frac{BE}{AD}$
$\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}=\frac{8}{12}$
$\therefore$ $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}=\frac{2}{3}$.