Question

In the given figure drawn, seg $BE\perp$ set $AB$ and seg $BA\perp$ seg $AD$.
If $BE=6$ and $AD=9$, find $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}$

Answer 1

Given, $\Delta ABE$ and $\Delta BAD$ have the same base and $BE=6$ and $AD=9$
Now, $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}=\frac{BE}{AD}$ ($\because$ Triangle having equal base)
$\therefore$ $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}=\frac{6}{9}$
$\therefore$ $\frac{A\left(\Delta ABE\right)}{A\left(\Delta BAD\right)}=\frac{2}{3}$.