Question

In the given figure find $\angle P$ (in degrees)

Answer 1

By angle sum of property of a triangle
$\angle P+{47}^{\circ }+{52}^{\circ }={180}^{\circ }$
$\angle P={180}^{\circ }-{47}^{\circ }-{52}^{\circ }$
=${180}^{\circ }-{99}^{\circ }$
=${81}^{\circ }$