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Question

In the given figure, find the value of BAC. Given: ΔDEF is equilateral, CBA =40, FEC =50 and DE is parallel to BC.


A

110

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B

50

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C

60

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D

70

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Solution

The correct option is D

70


Given: DEBC, so ADE =DBF= 40(corresponding angle)

AED = 180- (50+60) = 70 (Linear pair of angles)

AED = ECB=70 (Corresponding Angles);

Now consider ΔADE having AED & ADE is equal to 70 and 40 respectively.

For determining the DAE (or BAC) = 180- (70+40) = 70.


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