In the given figure, if AB = CD and D is the midpoint of BC, then which of the following is true ?
△ADB≅△ADC by SSS postulate
AD bisects ∠BAC
In △ABD and △ACD
(i) AB = AC .........(given)
(ii) BD = CD .........(given)
(iii) AD = AD ..........(common)
(iv)△ABD≅△ACD ......(SSS Postulate)
(v) ∠BAD=∠CAD .....(cpct)
∴ AD bisects ∠ BAC
(vi) ∠ABD=∠ACD .....(cpct)
If ∠BAC=80∘, then ∠ABD=∠ACD=50∘ (and not 80∘)
Hence (B) and (C)