And - CPB -4 x -5- then x -A- 15-B- 20-C- 30-D- 25-

The correct option is B 20^∘ ∠ APD = ∠ BPC .......(vertically opposite angles) ⇒ 3x+15 = 4x 5 ⇒ 15 + 5 = 4x 3x ⇒ 20 = x^∘ ⇒ x =20^∘ ...

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Byju's Answer

Standard VI

Mathematics

Vertically Opposite Angles

and ∠ CPB =4 ...

Question

In the given figure, if $∠ A P D$ = (3x + 15)° and $∠ C P B$ = (4x - 5)°, then x = ___.

$15^{\circ}$

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$20^{\circ}$

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$25^{\circ}$

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$30^{\circ}$

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Solution

The correct option is B
$20^{\circ}$

$∠ A P D$ = $∠ B P C$ .......(vertically opposite angles)

$\Rightarrow 3 x + 15 = 4 x - 5$

$\Rightarrow 15 + 5 = 4 x - 3 x$

$\Rightarrow 20 = x^{\circ}$
$\Rightarrow x = 20^{\circ}$

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In the given figure, if ∠APD = (3x + 15)° and ∠CPB = (4x - 5)°, then x = ___.

The correct option is B 20∘ ∠APD = ∠BPC .......(vertically opposite angles) ⇒3x+15=4x−5 ⇒15+5=4x−3x ⇒20=x∘ ⇒x=20∘

In the given figure, if $∠ A P D$ = (3x + 15)° and $∠ C P B$ = (4x - 5)°, then x = ___.

The correct option is B
$20^{\circ}$

$∠ A P D$ = $∠ B P C$ .......(vertically opposite angles)

$\Rightarrow 3 x + 15 = 4 x - 5$

$\Rightarrow 15 + 5 = 4 x - 3 x$

$\Rightarrow 20 = x^{\circ}$
$\Rightarrow x = 20^{\circ}$