In the given figure if BE = CF, then which of these following options is correct?

$Δ A B C ≅ Δ A C F$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$Δ A B E ≅ Δ A C F$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$Δ A B E ≅ Δ C A F$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$Δ A B C ≅ Δ A F C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$Δ A B E ≅ Δ A C F$

In $Δ A B E a n d Δ A C F,$
BE = CF [given]
$∠ C F A = ∠ B E A = 90^{\circ}$
$∠ A$ is common.
Hence, $Δ A B E ≅ Δ A C F$ [by A.A.S. Criterion]

Suggest Corrections

Similar questions

If $Δ A B C$ $≅$ $Δ D E F$ by S.S.S. congruence, then which of the following options is correct?

Join BYJU'S Learning Program