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Exterior Angle of a Triangle = Sum of Opposite Internal Angles

In the given ...

Question

In the given figure, if EC || AB, ∠ECD = 70° and ∠BDO = 20°, then ∠OBD is

(a) 20°

(b) 50°

(c) 60°

(d) 70°

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Solution

In the given figure,,and . We need to find.

Here, and CD is the transversal, so using the property, “corresponding angles are equal”, we get

Also, using the property, “an exterior angle of a triangle is equal to the sum of the two opposite interior angles”, in ΔOBD, we get,

Thus,

Therefore, the correct option is (b).

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Similar questions

In the given figure, AB||CD. If $∠ E A B = 50^{\circ}$ and $∠ E C D = 60^{\circ}$ then $∠ A E B = ?$

$(a) 50^{\circ}$

$(b) 60^{\circ}$

$(c) 70^{\circ}$

$(d) 55^{\circ}$

Q. In the given figure, AB || CD. If ∠EAB = 50° and ∠ECD = 60°, then ∠AEB = ?
(a) 50°
(b) 60°
(c) 70°
(d) 55°

Mark (✓) against the correct answer
In the given figure, ∠A = 50°, CE || BA and ∠ECD = 60°
Then, ∠ACB = ?

(a) 50°
(b) 60°
(c) 70°
(d) 80°

Q. In the given figure,

C E ⊥ A B,

∠ A C E = 20^{\circ}

∠ A B D = 50^{\circ}

∠ B D A

In the figure, if $E C | | A B, ∠ E C D = 70^{\circ}$ and $∠ B D O = 20^{\circ}, t h e n ∠ O B D$ is

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Exterior Angle of a Triangle = Sum of Opposite Internal Angles

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