In the given figure, m = ___.

$10^{\circ}$

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$20^{\circ}$

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$30^{\circ}$

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$40^{\circ}$

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Solution

The correct option is B
$20^{\circ}$

(i) $∠ B C A = 180^{\circ} - 140^{\circ}$ . . . . (linear pair)

$40^{\circ}$

(ii) $4 m^{\circ} = 2 m^{\circ} + 40^{\circ}$ . . . (exterior angle theorem)

$2 m^{\circ} = 40^{\circ}$

$m = 20^{\circ}$

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