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Question

In the given figure, O is the centre of a circle. AB and CD are its two chords. If OMAB, ONCD and OM=ON, then


A

ABCD

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B

AB<CD

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C

AB>CD

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D

AB=CD

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Solution

The correct option is D

AB=CD


Step 1- Comparing given data

From the given data we conclude that,

Both the chords AB and CD are placed at the same distance from the center of the circle O.

Step 2- chords equidistant from the center of a circle.

So, applying the theorem of chords equidistant from the center of a circle are equal.

We can conclude that,

The length of AB will be equal to the length of CD.

Hence, AB=CD

Hence, option (D) is the correct answer.


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