In the given figure, O is the centre of the circle and ∠ ABC=55∘. Calculate the values of x and y.
x=110∘
y=125∘
In Δ OBC,
Ext. ∠ AOC=∠ OBC+∠ BCO
=55∘+55∘=110∘
∴ x=110∘
Now in cyclic quadrilateral, ABCD
∠ ADC+∠ ABC=180∘⇒ y+55∘=180∘
∴ y=180∘−55∘=125∘