In the given figure, O is the centre of the circle, arc ABC subtends an angle of $130^{\circ}$ at the centre. If AB is extended to P, find $∠ P B C$

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Solution

$∠ P B C = 65^{\circ}$ (If one side of a cyclic quadrilateral is produced, then the exterior angle is equal to the interior opposite opposite angle)

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Q. In the given figure, O is the centre of the circle and arc ABC subtends an angle of 130° at the centre. If AB is extended to P, find ∠PBC.

In the given figure, O is the centre of the circle and arc ABC subtends an angle of $130^{\circ}$ at the centre. If AB is extended to P, find $∠ P B C .$

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is the centre of the circle. The angle subtended by the arc

B C D

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In the given figure, O is the centre of the circle, arc ABC subtends an angle of 130∘ at the centre. If AB is extended to P, find ∠PBC undefinedundefinedundefinedundefined

∠PBC=65∘ (If one side of a cyclic quadrilateral is produced, then the exterior angle is equal to the interior opposite opposite angle)

In the given figure, O is the centre of the circle, arc ABC subtends an angle of $130^{\circ}$ at the centre. If AB is extended to P, find $∠ P B C$

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undefined
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$∠ P B C = 65^{\circ}$ (If one side of a cyclic quadrilateral is produced, then the exterior angle is equal to the interior opposite opposite angle)