Question

In the given figure, $\angle$P $\cong$ $\angle$R seg PQ $\cong$ seg RQ

Prove that, $∆$ PQT $\cong$ $∆$ RQS

Answer 1

In △PQT and △RQS
∠P = ∠R (Given)
PQ = RQ (Given)
∠Q = ∠Q (Common)
By ASA test of congruency
△PQT ≅ △RQS