Question

In the given figure PA = 3 cm and PT = 4 cm, the value of PB is equal to

Answer 1

If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then $PA\times PB=P{T}^2$
Substituting the value we get
$3\times PB=4^2$
$PB=\frac{4^2}{3}$
$PB=\frac{16}{3}$ cm