wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure point A and C are on the horizontal ground & A and B are in same vertical plane. Simultaneously bullets are fired from A, B and C and they collide at D. The bullet at B is fired horizontally with speed of 725 km/hr and the bullet at C is projected vertically upward at velocity of 545 km/hr. Find velocity of the bullet projected from A in m/s.


Open in App
Solution

Velocity of bullet B, VB=725 km/h=4 m/s
Velocity of bullet C, VC=545 km/h=3 m/s
In this situation, for the three bullets to collide
Along x-axis
Horizontal distance covered by the bullet A must be equal to the horizontal distance covered by bullet B
ucosθ×t=4×tucosθ=4 m/s
Along y-axis
Vertical distance covered by the bullet A must be equal to the vertical distance covered by bullet C
usint12×gt2=3×t12gt2usinθ×t=3×tusinθ=3 m/s
Hence, velocity of projection of bullet from A=32+42=5 m/s
Alternatively:
For collision u=u2c+u2B=(725×518)2+(545×518)2=42+32=5 m/s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Human Cannonball
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon