In the given figure, PQ || RS. Find the values of a, b and c.
A
20°, 40°, 120°
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B
10°, 60°, 110°
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C
30°, 50°, 100°
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D
15°, 55°, 110°
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Solution
The correct option is A 20°, 40°, 120° Given, PQ || RS, and AC and BC are the transversals. ∠BCS=∠PBC (Since alternate interior angles are equal) ⇒b=40∘
Similarly, ∠RCA=∠BAC ⇒c=120∘
We know that sum of angles on a straight line is 180 degrees. ⇒c+a+b=180° ⇒120∘+a+40∘=180∘ ⇒a=180∘−160∘=20∘