In the given figure- PQR is a straight line- If -PQS - 110- - find - RQS-

From figure: ∠PQS nbsp; + nbsp; ∠RQS = 180^∘ nbsp;(Sum of angles lying on a straight line) ⇒ 110^∘+∠ RQS = 180^∘ ∠ RQS = 180^∘ 110^∘ ∠ RQS = 70^∘ nbs ...

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Standard VI

Mathematics

Finding Unknown Angles

In the given ...

Question

In the given figure; PQR is a straight line. If $∠$ PQS = $110^{\circ}$ ; find $∠$ RQS.

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Solution

From figure:
$∠$ PQS + $∠$ RQS = $180^{\circ}$ (Sum of angles lying on a straight line)
$\Rightarrow 110^{\circ} + ∠ R Q S = 180^{\circ} ∠ R Q S = 180^{\circ} - 110^{\circ} ∠ R Q S = 70^{\circ}$

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In the given figure; PQR is a straight line. If ∠PQS = 110∘ ; find ∠ RQS.

From figure: ∠PQS + ∠RQS = 180∘ (Sum of angles lying on a straight line) ⇒ 110∘+∠RQS=180∘∠RQS=180∘−110∘∠RQS=70∘

In the given figure; PQR is a straight line. If $∠$ PQS = $110^{\circ}$ ; find $∠$ RQS.

From figure:
$∠$ PQS + $∠$ RQS = $180^{\circ}$ (Sum of angles lying on a straight line)
$\Rightarrow 110^{\circ} + ∠ R Q S = 180^{\circ} ∠ R Q S = 180^{\circ} - 110^{\circ} ∠ R Q S = 70^{\circ}$