In the given figure, ∆PQR is an isosceles triangle in which PQ=QR, determine the value of x.

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Solution

Given:- PQ=QR

Therefore in triangle PQR

PQ = QR

As we know that angles opposite to equal sides are equal.

So ∠PRQ = ∠QPR =45°

As ∠PRQ = ∠QPR =45°

Using angle sum property of a triangle,
∠PRQ + ∠QPR + x= 180 degrees
90° + x= 180°
x = 180° - 90°
x=90°

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In the given figure, ∆PQR is an isosceles triangle in which PQ=QR, determine the value of x.

Given:- PQ=QR Therefore in triangle PQR PQ = QR As we know that angles opposite to equal sides are equal. So ∠PRQ = ∠QPR =45° As ∠PRQ = ∠QPR =45° Using angle sum property of a triangle, ∠PRQ + ∠QPR + x= 180 degrees 90° + x= 180° x = 180° - 90° x=90°

Given:- PQ=QR

Therefore in triangle PQR

PQ = QR

As we know that angles opposite to equal sides are equal.

So ∠PRQ = ∠QPR =45°

As ∠PRQ = ∠QPR =45°

Using angle sum property of a triangle,
∠PRQ + ∠QPR + x= 180 degrees
90° + x= 180°
x = 180° - 90°
x=90°