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Question

In the given figure, quadrilateral ABCD is circumscribed. The circle touches the sides AB,BC,CD,DA at P,Q,R,S respectively. If AP=9cm,BP=7cm,CQ=5cm,DR=6cm, find the perimeter of quad. ABCD
239527_36706c426b9d4064ac53c8ef7269fffc.png

A
54cm
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B
44cm
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C
24cm
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D
64cm
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Solution

The correct option is C 54cm
ABCD is a quadrilateral and let O be the center of the circle inscribed in the quadrilateral.
AB, BC, CD and AD are the tangent to the circle at P, Q, R and S, AP=9, PB=7, QC=5 and DR=6
We know that the lengths of the two tangents from a point to circle are equal.
Thus, AP=AS=9 cm
BP=BQ=7 cm
CQ=CR=5 cm
DR=DS=6 cm
Perimeter of quadrilateral ABCD=AB+BC+CD+AD
=AP+BP+BQ+CQ+CR+DR+DS+AS
=9+7+7+5+5+6+6+9
=54 cm

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