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Question

In the given figure, the position-time graph of a particle of mass 0.1kg is shown. The impulse at t=2sec is:
430487_e8e9ce463e414dce921367587d9d3740.png

A
0.2kg m sec1
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B
0.2kg m sec1
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C
0.1kg m sec1
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D
0.4kg m sec1
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Solution

The correct option is B 0.2kg m sec1
Step 1: Initial velocity
Velocity is given by the slope of the displacement-time graph.
From t=0 to t=2s
Slope =Displacementtime=4020=2

u=2m/s

Step 2: Final velocity
At t=2s, Slope of xt graph is zero
v=0m/s

Step 3: Impulse
Impulse is defined as change in momentum.
I=m(vu)
=0.1kg×(02m/s)
=0.2kg m s1
Hence, Option(B) is correct.

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