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Question

In the given figure, the position - time graph of a particle of mass 0.1 kg is shown. The magnitude of impulse at t=2 sec is:

A
0.2 kg -m/sec
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B
0.2 kg -m/sec
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C
0.1 kg -m/sec
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D
0.4 kg -m/sec
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Solution

The correct option is A 0.2 kg -m/sec
We know that slope of position-time graph gives the velocity of particle.
Velocity of particle at t<2 sec
u=42 m/s.

simillarly,
Velocity of particle at t>2 sec
V=0 m/s.

Also,
|Imulse(J)|=|Change in momentum|
|J|=ΔP=|m(vu)|
=0.1(042)
=0.2 kg -m/sec

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