In the given figure, the position - time graph of a particle of mass 0.1 kg is shown. The magnitude of impulse at t=2 sec is:
A
0.2 kg -m/sec
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B
−0.2 kg -m/sec
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C
0.1 kg -m/sec
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D
−0.4 kg -m/sec
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Solution
The correct option is A0.2 kg -m/sec We know that slope of position-time graph gives the velocity of particle. ∴Velocity of particle at t<2 sec u=42 m/s.
simillarly,
Velocity of particle at t>2 sec V=0 m/s.
Also,
|Imulse(J)|=|Change in momentum|
|J|=ΔP=|m(v−u)| =∣∣∣0.1(0−42)∣∣∣ =0.2 kg -m/sec