In the given figure, the value of x (in cm) is :
In △APBand△QPR,
PAPQ=2.46=25
PBPR=3.28=25
⇒PAPQ=PBPR
and ∠APB=∠QPR
So, By SAS Similarity,
△APB∼△QPR
⇒PAPQ=ABQR
⇒25=2x
⇒x=2×52
⇒x=5 cm
Hence, Option B is correct.
In the given figure, DE||BC such that AD = x cm, DB = (3x + 4) cm, AE = (x + 3) cm and EC = (3x + 19) cm. Find the value of x.