Question

In the given figure, $△ABC$ ~ $△BDC$. Identify the equal angles in the triangles.

$\begin{array}{cc}1.\angle DBC=\square & A:\angle BCA\\ 2.\angle BDC=\square & B:\angle BAC\\ 3.\angle DCB=\square & C:\angle ABC\end{array}$​

• A. 1 - B, 2 - C, 3 - A
• B. 1-C, 2 - B, 3- A
• C. 1 - B, 2 - A, 3 - B
• D. 1 - A, 2 - C, 3 - B

Answer 1

The correct option is A

1 - B, 2 - C, 3 - A

In the question it is given that $△ABC$ ~ $△BDC$.

The following will be the corresponding angles of the two triangles

$\angle ACB$ = $\angle BCD$ , $\angle ABC$ = $\angle BDC$ and $\angle BAC$ = $\angle DBC$.