In the given figure use the similarity of the given triangles to find the value of BD. ∠ABC=∠BDC=90^o
AB=3, BC=4, AD=2 BD=?

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Solution

The correct option is C

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Question 14
In the given figure, AB=BC and AD =BD = DC.

The number of isosceles triangles in the figure is
a) 1
b) 2
c) 3
d) 4

Question 14
In the given figure, AB=BC and AD =BD = DC.

The number of isosceles triangles in the figure is
a) 1
b) 2
c) 3
d) 4

In the given figure, ABC is a triangle in which ∠ABC < 90° and AD ⊥ BC. Prove that AC² = AB² + BC² − 2BC.BD.

∠ A B C = 90^{o}

B D ⊥ A C

[Δ A B C \sim Δ B D C \Rightarrow \frac{A B}{B D} = \frac{B C}{D C}]

In the given figure ∠ABC=∠BDC=90^o each. Choose the correct similarity from the given choices.

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