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Question

In the given figure, ABC is circumscribed. The circle touches the sides AB, BC and CA at P, Q, R respectively. If AP = 5 cm, BP = 7 cm, AC = 14 cm and BC = x cm, find the value of x.


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Solution

AR = AP = 5 cm

RC = AC – AR = 14 – 5 = 9

QC = RC = 9

BQ = BP = 7

BC = BQ + QC = 7 + 9 = 16 cm

Therefore the value of x= 16 cm


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