In the given figure, which congruence rule can be used to prove that △ABC ≅ △CDA?
In △ABC and △CDA, AC = CA (common side) AB = CD (given) Also, ∠ACB = ∠CAD = 90∘ (from the figure) Therefore, △ABC≅△CDA (by RHS congruence condition)
In ΔABD, AB = AD and AC is perpendicular to BD. State the congruence rule by which ΔACB≅ΔACD.
In the given figure, which property of congruence can be used to prove that △ABC≅△CDA?
Is it necessary to have a 90° angle in rhs congruence rule or by having equal hypotenuse and equal side we can apply RHS congruence rule?